If y + 3 x = 0 is the equation of a chord of the circle x 2 + y 2 - 30 x = 0 , then the equation of the…

If y+3x=0 is the equation of a chord of the circle x2+y2-30x=0, then the equation of the circle with this chord as diameter is :
  1. x2+y2+3x-9y=0
  2. x2+y2-3x+9y=0
  3. x2+y2+3x+9y=0
  4. x2+y2-3x-9y=0

Solution



To find point of intersection of given chord y=-3x with the given circle x2+y2-30x=0 eliminate y from two equations
Point of intersection  
x2+9x2-30x=0
10x x-3=0
x=0 or x=3
Therefore, y = 0 and y =-9 are the corresponding ordinates.
Point of intersection (0, 0), (3, -9)
Diametric form of equation of circle,
x x-3+yy+9=0
x2+y2-3x+9y=0 .

Asked in: JEE Main 2015 (10 Apr Online)

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