If \(x+5=0\) is the directrix and \((-3,0)\) the vertex of a parabola, then equation of this parabola is ____

If \(x+5=0\) is the directrix and \((-3,0)\) the vertex of a parabola, then equation of this parabola is ____
  1. \(y^2=8(x+3)\)
  2. \(y^2=8(x-3)\)
  3. \(x^2=8(y+3)\)
  4. \(x^2=8(y-3)\)

Solution

Given parabola is,
So, its equation is, \(y^2=4 a(x-(-3)\) Where \(a=2\) units. \(\therefore \quad y^2=8(x+3)\)

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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