If Δ = x − 2 2 x − 3 3 x − 4 2 x − 3 3 x − 4 4 x − 5 3 x − 5…

If Δ=x−22x−33x−42x−33x−44x−53x−55x−810x−17=Ax3+Bx2+Cx+D, then B+C  is equal to :
  1. -1
  2. 1
  3. -3
  4. 9

Solution

Δ=x−22x−33x−42x−33x−44x−53x−55x−810x−17

Applying R2→R2-R1, R3→R3-R2, we get

Δ=x−22x−33x−4x-1x−1x−1x−22x−26x−2=x-1x-2x−22x−33x−4111126

=-3x3+12x2-15x+6

∴B+C=12-15=-3

Asked in: JEE Main 2020 (03 Sep Shift 1)

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