If $X$ is a random variable with probability mass function $P(x)=k x, x=1,2,3$ $\qquad =0$, $\quad$ otherwise then, $k=$.

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Aicharya · Accepted Answer

$\begin{array}{|l|l|l|l|} \hline x & 1 & 2 & 3 \ \hline P(x) & k & 2 k & 3 k \ \hline \end{array}$ Since, the function is a p.m.f. $\begin{aligned} & \therefore \sum \mathrm{P}\left(\mathrm{x}_{\mathrm{i}}\right)=1 \ & \therefore \mathrm{k}+2 \mathrm{k}+3 \mathrm{k}=1 \ & \therefore \mathrm{k}=1 / 6 \end{aligned}$

If \(X\) is a random variable with probability mass function \(P(x)=k x, x=1,2,3\) \(\qquad =0\), $\quad$…

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