If $f(x)=3[x]+\{x+1\}$, where $[x]$ is greatest integer function of $x$ and $\{x\}$ is fractional part function of $x$, then $f(-1.32)=$

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{f}(\mathrm{x})=3[\mathrm{x}]+5\{\mathrm{x}+1\} \ & \mathrm{x}=-1.32 \Rightarrow[\mathrm{x}]=[-1.32]=-2 \ & 	ext { Also } \mathrm{x}+1=-1.32+1=-0.32 \ & 	herefore[\mathrm{x}+1]=[-0.32]=-1 	ext { and }\{\mathrm{x}+1\}=0.68 \ & 	herefore \mathrm{f}(\mathrm{x})=3(-2)+5(0.68) \ & =-6+3.4=-2.6 \end{aligned}$

If $f(x)=3[x]+\{x+1\}$, where $[x]$ is greatest integer function of $x$ and $\{x\}$ is fractional part…

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