If $[x]^2-5[x]+6=0$, where $[x]$ denotes the greatest integer function, then
If $[x]^2-5[x]+6=0$, where $[x]$ denotes the greatest integer function, then
- $x \in[2,3)$
- $x \in[2,3]$
- $\quad x \in[2,4]$
- $\quad x \in[2,4)$
Solution
Given:
$\begin{aligned}
& {[x]^2-5[x]+6=0} \\
& \text { Let }[x]=\mathrm{a} \\
& \Rightarrow \mathrm{a}^2-5 \mathrm{a}+6=0 \\
& \Rightarrow(\mathrm{a}-2)(\mathrm{a}-3)=0 \\
& \Rightarrow \mathrm{a}=2 \text { or } \mathrm{a}=3 \\
& \Rightarrow[x]=2 \text { or }[x]=3 \\
& \Rightarrow x \in[2,3) \text { or } x \in[3,4) \\
& \Rightarrow x \in[2,4)
\end{aligned}$
Asked in: MHT CET 2024 (11 May Shift 1)
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