If we add $3 \mathrm{~kg}$ load to the hanger of sonometer, the fundamental frequency becomes two times its initial value. The initial load must be

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Aicharya · Accepted Answer

$\mathrm{n} \propto \sqrt{\mathrm{T}} \quad \frac{\mathrm{n}_{1}}{\mathrm{n}_{2}}=\sqrt{\frac{\mathrm{T}_{1}}{\mathrm{~T}_{2}}}$ $\frac{1}{2}=\left(\frac{T}{T+3}\right)^{1 / 2} \Rightarrow \frac{1}{4}=\frac{T}{T+3}$ $1+\frac{3}{T}=4$ $\frac{3}{T}=3 \Rightarrow T=1 \mathrm{~kg}$

If we add $3 \mathrm{~kg}$ load to the hanger of sonometer, the fundamental frequency becomes two times its…

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