If variance of $x_1, x_2 \ldots \ldots, x_{\mathrm{n}}$ is $\sigma_x^2$, then the variance of $\lambda x_1, \lambda x_2, \ldots \ldots, \lambda x_n(\lambda
eq 0)$ is

Question

If variance of $x_1, x_2 \ldots \ldots, x_{\mathrm{n}}$ is $\sigma_x^2$, then the variance of $\lambda x_1, \lambda x_2, \ldots \ldots, \lambda x_n(\lambda 
eq 0)$ is

Aicharya · Accepted Answer

When each item of a data is multiplied by $\lambda$, variance is multiplied by $\lambda^2$. $	herefore \quad$ New variance $=\lambda^2 \cdot \sigma_x^2$

If variance of $x_1, x_2 \ldots \ldots, x_{\mathrm{n}}$ is $\sigma_x^2$, then the variance of $\lambda x_1,…

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