If $4^3+8^3+12^3+\ldots$ up to $n$ terms $=k n^2(n+1)^2$ (for all $n \in \mathrm{N}$), then $k=$

If $4^3+8^3+12^3+\ldots$ up to $n$ terms $=k n^2(n+1)^2$ (for all $n \in \mathrm{N}$), then $k=$
  1. 4
  2. 8
  3. 16
  4. 32

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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