If uncertainty in position and velocity are equal then uncertainty in momentum will be

Question

Aicharya · Accepted Answer

$\Delta \mathrm{x}=\Delta \mathrm{v}$
$\Delta \mathrm{x} \cdot \Delta \mathrm{v}=\frac{\mathrm{h}}{4 \pi \mathrm{m}}$
$\Delta \mathrm{v}^{2}=\frac{\mathrm{h}}{4 \pi \mathrm{m}}$
$\therefore \quad \Delta v=\sqrt{\frac{h}{4 \pi m}}$
$\Delta \mathrm{p}=\mathrm{m} \Delta \mathrm{v}=\mathrm{m} \sqrt{\frac{\mathrm{h}}{4 \pi \mathrm{m}}}$
$=\frac{1}{2} \sqrt{\frac{\mathrm{hm}}{\pi}}$ *

If uncertainty in position and velocity are equal then uncertainty in momentum will be

Solution