If two fair dice are rolled, then the probability that the sum of the numbers on the upper faces is at least…

If two fair dice are rolled, then the probability that the sum of the numbers on the upper faces is at least 9 , is
  1. $\frac{1}{3}$
  2. $\frac{4}{11}$
  3. $\frac{5}{18}$
  4. $\frac{5}{36}$

Solution

$\begin{aligned} & \text { Total number of outcomes }=36 \\ & \text { Favourable number of outcomes }=10 \\ & \text { i.e., }\{(3,6),(4,5),(4,6),(5,4),(5,5),(5,6), \\ & (6,3),(6,4),(6,5),(6,6)\} \\ \therefore \quad & \text { Required probability }=\frac{10}{36}=\frac{5}{18}\end{aligned}$

Asked in: MHT CET 2024 (15 May Shift 2)

Practice more Probability questions on Aicharya