If three distinct vertices are chosen at random from the vertices of a cube, then the probability that they…

If three distinct vertices are chosen at random from the vertices of a cube, then the probability that they form the vertices of an equilateral triangle, is
  1. $\frac{1}{7}$
  2. $\frac{2}{7}$
  3. $\frac{1}{2}$
  4. $\frac{1}{8}$

Solution

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Asked in: AP EAMCET 2018 (24 Apr Shift 2)

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