If three angles of a quadrilateral are equal and the fourth is $72^{\circ}$, each equal angle is:

If three angles of a quadrilateral are equal and the fourth is $72^{\circ}$, each equal angle is:
  1. $92^{\circ}$
  2. $96^{\circ}$
  3. $108^{\circ}$
  4. $120^{\circ}$

Solution

$3x + 72 = 360 \Rightarrow 3x = 288 \Rightarrow x = 96^{\circ}$.

Asked in: IMO

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