If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to
If there are n capacitors in parallel connected to V volt source, then the energy stored is equal to
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$\mathrm{CV}$
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$\frac{1}{2} \mathrm{nCV}^2$
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$\mathrm{CV}^2$
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$\frac{1}{2 n} CV^2$
Solution
$E=\sum \frac{1}{2} C V^2=\frac{1}{2} n C V^2$
Asked in: JEE Main 2002
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