If there are 999 bases in an RNA that codes for a protein with 333 amino acids, and the base at position 901…

If there are 999 bases in an RNA that codes for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?
  1. 1
  2. 11
  3. 33
  4. 333

Solution

33 codons will be altered if the 901st base is deleted and RNA has only 998 bases instead of 999 bases
Total bases present in RNA = 999
Bases left after deletion of 901st base
In RNA = 999 - 901 = 98
3 codon= 1 amino acid
Therefore 98/3= approx 33
A number of codons present in 98 bases= 33 (Approximately as three codons code for one amino acid).

Asked in: NEET 2017

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