If $\tan ^{-1} a+\tan ^{-1} b+\tan ^{-1} c=\pi$, then which of the following statement is true?
If $\tan ^{-1} a+\tan ^{-1} b+\tan ^{-1} c=\pi$, then which of the following statement is true?
- $a+b-c=a b c$
- $a+b+c=2 a b c$
- $a b c=1$
- $a+b+c=a b c$
Solution
$\begin{aligned} & \tan ^{-1} a+\tan ^{-1} b+\tan ^{-1} c=\pi \\ & \Rightarrow \tan ^{-1}\left(\frac{a+b+c-a b c}{1-a b-b c-c a}\right)=\pi \\ & \Rightarrow \frac{a+b+c-a b c}{1-a b-b c-c a}=\tan \pi=0 \\ & \Rightarrow a+b+c-a b c=0 \\ & \Rightarrow a+b+c=a b c\end{aligned}$
Asked in: MHT CET 2023 (10 May Shift 2)
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