If $f(x)=\left\{\begin{array}{ll}{[x]} & \text { if }-3 < x \leq-1 \\ |x| & \text { if }-1 < x < 1 \\ |[x]|…

If $f(x)=\left\{\begin{array}{ll}{[x]} & \text { if }-3 < x \leq-1 \\ |x| & \text { if }-1 < x < 1 \\ |[x]| & \text { if } 1 \leq x < 3\end{array}\right.$ then the set $(x: f(x) \geq 0)$ is equal to
  1. $(-1,3)$
  2. $[-1,3)$
  3. $(-1,3]$
  4. $[-1,3)$

Solution

Given that, $ \begin{aligned} & \qquad f(x)=\left\{\begin{array}{l} {[x] \text { if }-3 < x \leq-1} \\ |x| \text { if }-1 < x < 1 \\ |[x]| \text { if } 1 \leq x < 3 \end{array}\right. \\ & \text { When }-3 < x \leq-1, f(x)=[x] \\ & \Rightarrow \quad f(x) < 0 \end{aligned} $

Asked in: AP EAMCET 2004

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