If $A=\left[\begin{array}{ccccc}0 & 1 & 2 & 3 & 4 \\ 0 & 2 & 4 & 8 & 12 \\ 0 & 0 & 0 & 4 &…

If $A=\left[\begin{array}{ccccc}0 & 1 & 2 & 3 & 4 \\ 0 & 2 & 4 & 8 & 12 \\ 0 & 0 & 0 & 4 & 8\end{array}\right]$, then the rank of $A$ is
  1. $1$
  2. $2$
  3. $3$
  4. $4$

Solution

$A=\left[\begin{array}{lllll}0 & 1 & 2 & 3 & 4 \\ 0 & 2 & 4 & 8 & 12 \\ 0 & 0 & 0 & 4 & 8\end{array}\right]$ $\mathrm{R}_2 \rightarrow \mathrm{R}_2-2 \mathrm{R}^1$ $\begin{aligned} & \sim\left[\begin{array}{lllll}0 & 1 & 2 & 3 & 4 \\ 0 & 0 & 0 & 2 & 4 \\ 0 & 0 & 0 & 4 & 8\end{array}\right] \\ & \because\left|\begin{array}{cc}3 & 4 \\ 2 & 4\end{array}\right|=12-8=4 \uparrow 0\end{aligned}$ $\therefore$ Rank $=2$

Asked in: AP EAMCET 2022 (08 Jul Shift 1)

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