If $\sin \alpha=p$, then the quadratic equation whose roots are $\tan \frac{\alpha}{2}, \cot…
- $p x^2-2 x+p=0$
- $p x^2+2 x+p=0$
- $p x^2+x+p=0$
- $p x^2-x+p=0$
Solution


and product of roots $=\tan \frac{\alpha}{2} \times \cot \frac{\alpha}{2}=1$ So, equation required quadratic equation $ x^2-\frac{2}{p} x+1=0 \Rightarrow p x^2-2 x+p=0 $ Hence, option (a) is correct
Asked in: AP EAMCET 2019 (20 Apr Shift 2)