If $0 < x < \frac{\pi}{2}$ then the maximum area (in sq. units) of the triangle whose vertices are $(0,0)$,…

If $0 < x < \frac{\pi}{2}$ then the maximum area (in sq. units) of the triangle whose vertices are $(0,0)$, $(x, \cos x)$ and $\left(\sin ^3 x, 0\right)$ is
  1. $\frac{3 \sqrt{3}}{32}$
  2. $\frac{7 \sqrt{3}}{32}$
  3. $\frac{5 \sqrt{3}}{32}$
  4. $\frac{3 \sqrt{3}}{16}$

Solution

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Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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