If $\frac{x^2+5 x+1}{(x+1)(x+2)(x+3)}=\frac{a}{x+1}+\frac{b}{(x+1)(x+2)}+\frac{c}{(x+1)(x+2)(x+3)}$ then the…
- $\left[\begin{array}{cc}1 & 0 \\ -5 & 1\end{array}\right]$
- $\left[\begin{array}{cc}-1 & 0 \\ 5 & -1\end{array}\right]$
- $\left[\begin{array}{ll}1 & 0 \\ 5 & 1\end{array}\right]$
- $\left[\begin{array}{ll}1 & 0 \\ 1 & 5\end{array}\right]$
Solution
Asked in: AP EAMCET 2017 (25 Apr Shift 1)