If $k \in N$, then $3^{3 k}-26^k-1$ is divisible by
If $k \in N$, then $3^{3 k}-26^k-1$ is divisible by
- 676
- 8
- 64
- 26
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2020 (07 Oct Special)
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