If $\mathrm{f}(x)=\frac{x}{2-x}, \mathrm{~g}(x)=\frac{x+1}{x+2}$, then (gogof) $(x)=$

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$f(x)=\frac{x}{2-x}, g(x)=\frac{x+1}{x+2}$ $($ gof $)(x)=\frac{\frac{x}{2-x}+1}{\frac{x}{2-x}+2}$ $\begin{aligned} & 	ext { (gogof) }(x)=\frac{\frac{\frac{x}{2-x}+1}{x}+1}{\frac{\frac{x}{2-x}+2}{\frac{x}{2-x}+2}+2} \ & =\frac{\frac{x+2-x}{x+4-2 x}+1}{\frac{x+2-x}{x+4-2 x}+2} \end{aligned}$ $\begin{aligned} & =\frac{\frac{2}{4-x}+1}{\frac{2}{4-x}+2} \ & =\frac{2+4-x}{2+8-2 x} \ & =\frac{6-x}{10-2 x}\end{aligned}$

If $\mathrm{f}(x)=\frac{x}{2-x}, \mathrm{~g}(x)=\frac{x+1}{x+2}$, then (gogof) $(x)=$

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