If the wavelength of the first member of Lyman series of hydrogen is λ . The wavelength of the second member…

If the wavelength of the first member of Lyman series of hydrogen is λ. The wavelength of the second member will be
  1. 2732λ
  2. 3227λ
  3. 275λ
  4. 527λ

Solution

For Lyman series:

For first member, 1λ=13.6Z2hc112-122 ….. (i)

For second member, 1λ'=13.6Z2hc112-132 ….. (ii)

On dividing (i) and (ii), we get

λ'=2732λ

Asked in: JEE Main 2024 (31 Jan Shift 1)

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