If the wavelength of a photon is \(4000 Å\), then its energy will be
If the wavelength of a photon is \(4000 Å\), then its energy will be
- \(4.95 \times 10^{-19} \mathrm{~J}\)
- \(5.95 \times 10^{-19} \mathrm{~J}\)
- \(3.95 \times 10^{-19} \mathrm{~J}\)
- \(6.95 \times 10^{-19} \mathrm{~J}\)
Solution
Wavelength of photon, $\lambda=4000 \, \text{Å}=4 \times 10^{-7} \, \text{m}$ Energy of photon, $E=\frac{h c}{\lambda}$
$\begin{aligned}
& =\frac{6.62 \times 10^{-34} \times 3 \times 10^{8}}{4 \times 10^{-7}} \\
& =4.96 \times 10^{-19} \, \text{J} \approx 4.95 \times 10^{-19} \, \text{J}
\end{aligned}$
Asked in: AP EAMCET 2020 (21 Sep Shift 1)
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