If the velocity of a particle is υ = A t + B t 2 , where A and B are constants, then the distance travelled by it between 1 s and 2 s is:

Question

Aicharya · Accepted Answer

V = A t + B t 2 X = ∫ 0 t V d t ⇒ X = A t 2 2 + B t 3 3 t = 1 X 1 = A 2 + B 3 t = 2 X 2 = 2 A + 8 B 3 X 2 - X 1 = 3 A 2 + 7 B 3

If the velocity of a particle is υ = A t + B t 2 , where A and B are constants, then the distance travelled…