If the velocity of a particle is υ = A t + B t 2 , where A and B are constants, then the distance…

If the velocity of a particle is υ=At+Bt2, where A and B are constants, then the distance travelled by it between 1s and 2s is:
  1. 32A+4B
  2. 3A+7B
  3. 32A+73B
  4. A2+B3

Solution

V=At+Bt2

X= 0 t Vdt X=At22+Bt33

t=1

X1=A2+B3

t=2

X2=2A+8B3

X2-X1=3A2+7B3 ^

Asked in: JEE Mains - Motion In One Dimension - Test 3

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