If the variance of $6,7,8,9,10,11$ is $\sigma^2$, then the variance of $12,14,16,18,20,22$ is

If the variance of $6,7,8,9,10,11$ is $\sigma^2$, then the variance of $12,14,16,18,20,22$ is
  1. $2 \sigma^2$
  2. $4 \sigma^2$
  3. $100+2 \sigma^2$
  4. $100+4 \sigma^2$

Solution

Its a fundamental concept if each data is doubled then variance is 4 times. So, new variance $=(2)^2 \sigma^2=4 \sigma^2$

Asked in: AP EAMCET 2018 (24 Apr Shift 1)

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