If the value of ∫ 0 π / 2 sin 4 x · cos 2 x d x = π 32 then the value of ∫ 0…

If the value of 0π/2sin4x·cos2xdx=π32 then the value of 0π/2cos4x·sin2xdx=
  1. π32
  2. π64
  3. π4
  4. π8

Solution

Given, 0π2sin4x·cos2xdx=π32

0π2sin4π2-x·cos2π2-xdx=π32 abfxdx=abfa+b-xdx

0π2cos4x·sin2xdx=π32

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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