If the universal set $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$ and $A = \{2, 4, 6\}$, then $A'$ (complement) is
If the universal set $U = \{1, 2, 3, 4, 5, 6, 7, 8\}$ and $A = \{2, 4, 6\}$, then $A'$ (complement) is
- $\{1, 3, 5, 7, 8\}$
- $\{2, 4, 6\}$
- $\{1, 2, 3, 5, 7\}$
- $U$
Solution
$A' = U - A = \{1, 3, 5, 7, 8\}$.
Asked in: MH-SSC-9
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