If the two diagonals of a parallelogram are $\bar{i}+2 \bar{j}+3 \bar{k}$ and $-2 \bar{i}+\bar{j}-2 \bar{k}$…

If the two diagonals of a parallelogram are $\bar{i}+2 \bar{j}+3 \bar{k}$ and $-2 \bar{i}+\bar{j}-2 \bar{k}$, then the area of the parallelogram in square units is
  1. $\frac{3}{2} \sqrt{5}$
  2. $5 \sqrt{3}$
  3. $\sqrt{300}$
  4. $3 \sqrt{\frac{5}{2}}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 1)

Practice more Vectors questions on Aicharya