If the transverse and conjugate axes of hyperbola are equal, then its eccentricity is
- $\sqrt{3}$
- $\sqrt{2}$
- $\frac{1}{\sqrt{2}}$
- 2
Solution

$C D \rightarrow$ transverse axis $A B \rightarrow$ conjugate axis $ \Rightarrow \quad 2 b=2 a \Rightarrow a=b $ Using equation of hyperbola $\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ $ \left\{\because b^2=a^2\left(e^2-1\right)\right\} $ Now, $a^2=a^2\left(e^2-1\right) \Rightarrow e^2=2$ $ \Rightarrow \quad e=\sqrt{2} $
Asked in: AP EAMCET 2021 (23 Aug Shift 1)