If the total energy transferred to a surface in time t is 6 . 48 × 10 5 J , then the magnitude of the total…

If the total energy transferred to a surface in time t is 6.48×105 J, then the magnitude of the total momentum delivered to this surface for complete absorption will be :
  1. 2.46×10-3 kg m s-1
  2. 2.16×10-3 kg m s-1
  3. 1.58×10-3 kg m s-1
  4. 4.32×10-3 kg m s-1

Solution

As we know,

p=Ec, where c is velocity of light.

Therefore, p=6.48×1053×108=2.16×10-3 kg m s-1

Asked in: JEE Main 2024 (30 Jan Shift 2)

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