If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under…

If the time period $t$ of the oscillation of a drop of liquid of density $d$, radius $r$, vibrating under surface tension $s$ is given by the formula $t=\sqrt{r^{2 b} s^c d^{a / 2}}$. It is observed that the time period is directly proportional to $\sqrt{\frac{d}{s}}$. The value of $b$ should therefore be :
  1. $\frac{3}{4}$
  2. $\sqrt{3}$
  3. $\frac{3}{2}$
  4. $\frac{2}{3}$

Solution

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Asked in: JEE Main 2013 (23 Apr Online)

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