If the synthesis of ammonia from Haber's process is carried out with exactly the same starting conditions…
If the synthesis of ammonia from Haber's process is carried out with exactly the same starting conditions (of partial pressure and temperature) but using $\mathrm{D}_{2}$ (deuterium) in place of $\mathrm{H}_{2}$. Then
the equilibrium will be disturbed
the composition of reaction mixture will remain same at equilibrium.
Use of isotope in reaction will not produce ammonia.
At equilibrium rate of forward reaction will be greater than the rate of reverse reaction
Solution
The reaction mixtures starting either with $\mathrm{H}_{2}$ or $\mathrm{D}_{2}$ reach equilibrium with the same composition, except that $\mathrm{D}_{2}$ and $\mathrm{ND}_{3}$ are present instead of $\mathrm{H}_{2}$ and $\mathrm{NH}_{3}$.
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