If the symbolic form of the switching circuit is $[\sim \mathrm{pv}(\mathrm{p} \wedge \sim \mathrm{q})]…
If the symbolic form of the switching circuit is $[\sim \mathrm{pv}(\mathrm{p} \wedge \sim \mathrm{q})] \mathrm{v} \mathrm{q}$, then the current flows through the circuit onlyif
irrespective of status of the switches
one switch should be open and other should be closed
both switches should be closed
both switches should be open
Solution
$[\sim p \vee(p \wedge \sim q)] \vee q$
$=[(\sim p \vee p) \wedge(\sim p \vee \sim q)] \vee q$
$E[T \wedge(\sim p \vee \sim q)] \vee q$
$\equiv(\sim p \vee \sim q) \vee q$
$\equiv \sim p \vee(\sim q \vee q) \equiv \sim p \vee T \equiv T$
This shows that current flows irrespective of status of the switches.