If the sum of the first n terms of the series 3 +   75 +   243 +   507 + … is 435 3 ,…

If the sum of the first n terms of the series 3+ 75+ 243+ 507+ is 4353, then n equals:
  1. 13
  2. 15
  3. 29
  4. 18

Solution

3 1+25+ 81+ 169+=4353

3 1+5+9+13+Tn=4353

= 3×n22+n-14=4353

=2n+4n2-4n=870

=4n2-2n-870=0

=2n2-n-435=0

n=1± 1+4×2×4354

=1±594      n is +ve

n=1+594=15 

Asked in: JEE Main 2017 (08 Apr Online)

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