If the sum of squares of all real values of α , for which the lines 2 x - y + 3 = 0 , 6 x + 3 y + 1 = 0 and…

If the sum of squares of all real values of α, for which the lines 2x-y+3=0, 6x+3y+1=0 and αx+2y-2=0 do not form a triangle is p, then the greatest integer less than or equal to p is ________.

Solution

Given lines are $2x - y + 3 = 0$, $6x + 3y + 1 = 0$ and $\alpha x + 2y - 2 = 0$. These lines will not form a triangle if $\alpha x + 2y - 2 = 0$ is concurrent with $2x - y + 3 = 0$ and $6x + 3y + 1 = 0$ or parallel to either of them. Case-1: Concurrent lines $\Rightarrow \begin{vmatrix} 2 & -1 & 3 \\ 6 & 3 & 1 \\ \alpha & 2 & -2 \end{vmatrix} = 0$ $\Rightarrow 2(-6 - 2) + 1(-12 - \alpha) + 3(12 - 3\alpha) = 0$ $\Rightarrow -16 - 12 - \alpha + 36 - 9\alpha = 0$ $\Rightarrow -10\alpha + 8 = 0$ $\Rightarrow \alpha = \frac{4}{5}$ Case-2: Parallel lines $\frac{-\alpha}{6} = \frac{-2}{3}$, $-\frac{\alpha}{2} = \frac{-2}{-1}$ $\Rightarrow \alpha = 4$, $\alpha = -4$ $\Rightarrow P = 16 + 16 + \frac{16}{25}$ $[P] = [32 + \frac{16}{25}] = 32$

Asked in: JEE Main 2024 (27 Jan Shift 2)

Practice more Straight Lines questions on Aicharya