If the sum of first 11 terms of an A.P. , a 1 , a 2 , a 3 … … is 0 a 1 ≠ 0 then the sum of…

If the sum of first 11 terms of an A.P. ,a1,a2,a3 is 0a10 then the sum of the A.P a1,a3,a5,..a23 is ka1 where k is equal to
  1. -12110
  2. 12110
  3. 725
  4. -725

Solution

Let a1 be the first term and d be the common difference of A.P.

 S11=0 1122a1+10d=0

 a1+5d=0

 Now a1+a3+a5+.+a23=1222a1+12-12d =12a1+11d
=12a1-11a15
=-72a15

Asked in: JEE Main 2020 (02 Sep Shift 2)

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