If the sum 3 1 2 + 5 1 2 + 2 2 + 7 1 2 + 2 2 + 3 2 + .... . + up to 20 terms is equal to k 21 , then k is…

If the sum 312+512+22+712+22+32+.....+ up to 20 terms is equal to k21, then k is equal to 
  1. 240
  2. 120
  3. 60
  4. 180

Solution

S20=312+512+22+712+22+32+....+upto 20terms

=Σr=1202r+112+22+32+.... r2

=Σr=1202r+1r6r+12r+1

=6Σr=1201rr+1

=6Σr=1201r-1r+1

=611-12+12-13+13-14+....+120-121

=61-121

=6×2021

=12021

=k21

k=120

Asked in: JEE Main 2014 (09 Apr Online)

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