If the statement $p \vee \sim(q \wedge r)$ is false; then the truth values of $p, q$ and $r$ are respectively
- $\mathrm{F}, \mathrm{T}, \mathrm{F}$
- $T, F, F$
- $\mathrm{F}, \mathrm{T}, \mathrm{T}$
- $F, F, T$
Solution

$\therefore \quad$ From above table, $p \vee \sim(q \wedge r)$ is false, if $p=F$, $\mathrm{q}=\mathrm{T}, \mathrm{r}=\mathrm{T}$
Asked in: MHT CET 2024 (02 May Shift 1)