If the standard enthalpy of sublimation $\left(\Delta_{\mathrm{gos}} \mathrm{H}^{\circ}\right)$ of solid…

If the standard enthalpy of sublimation $\left(\Delta_{\mathrm{gos}} \mathrm{H}^{\circ}\right)$ of solid $\mathrm{CO}_2$, naphthalene, $\mathrm{Li}$ and $\mathrm{Na}$ are $25.2,73.0,162,108$ $\mathrm{kJ}$ mol respectively, the order of sublimation of these substances with temperature is
  1. $\mathrm{Na}>\mathrm{Li}>$ Naphthalene $>$ Solid $\mathrm{CO}_2$
  2. Solid $\mathrm{CO}_2>\mathrm{Na}>$ Naphthalene $>\mathrm{Li}$
  3. Solid $\mathrm{CO}_2>$ Naphthalene $>\mathrm{Na}>\mathrm{Li}$
  4. $\mathrm{Li}>\mathrm{Na}>$ Naphthalene $>$ Solid $\mathrm{CO}_2$

Solution

The lower the sublimation enthalpy, the lower is the heat required to sublime it and easier for that substance to get sublimed. Thus, the order of ease of sublimation will be:solid $\mathrm{CO}_2>\mathrm{Na}>\mathrm{Na}>\mathrm{Li}$

Asked in: AP EAMCET 2023 (16 May Shift 1)

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