If the speed of sound in air is $330\text{ m/s}$, then find the number of tones present in an open organ…
If the speed of sound in air is $330\text{ m/s}$, then find the number of tones present in an open organ pipe of length $1\text{ m}$ whose frequency is $\le 1000\text{ Hz}$. [AIIMS 2019]
2
4
8
6
Solution
Given, speed of sound, $v = 330\text{ m/s}$
Length of open organ pipe, $l = 1\text{ m}$
Frequency, $f = 1000\text{ Hz}$
For open organ pipe, fundamental frequency,
$f_o = \frac{v}{2l} = \frac{330}{2 \times 1} = 165\text{ Hz}$
$\therefore$ Number of tones present in the open organ pipe
$= \frac{f}{f_o} = \frac{1000}{165} = 6.06 \simeq 6$