If the side length of a face centered unit cell of a metal is $400 \mathrm{pm}$, approximate radius of the…
If the side length of a face centered unit cell of a metal is $400 \mathrm{pm}$, approximate radius of the metal in pm is $(\sqrt{2}=1.414)$
- 14.14
- 35.3
- 176.7
- 141.4
Solution
Edge/side length of a fcc $=400 \mathrm{pm}$
$\because$ For fcc
$
\begin{aligned}
r & =\frac{a}{2 \sqrt{2}} \\
\therefore \quad r & =\frac{400}{2 \times 1.414}=141.4 \mathrm{pm}
\end{aligned}
$
Asked in: AP EAMCET 2018 (24 Apr Shift 1)
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