If the roots of the quadratic equation $x^2-35 x+c=0$ are in the ratio $2: 3$ and $c=6 \mathrm{~K}$, then $\mathrm{K}=$

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Aicharya · Accepted Answer

Let roots of $x^3-35 x+c=0$ be $2 t$ and $3 t$ Now, $2 t+3 t=\frac{35}{1} \Rightarrow 5 t=35 \Rightarrow t=7$ Now, $2 t+3 t=\frac{35}{1} \Rightarrow 5 t=35 \Rightarrow t=7$ and $2 t 	imes 3 t=c \Rightarrow c=6 	imes 49$ $\Rightarrow 6 K=6 	imes 49 \Rightarrow K=49$

If the roots of the quadratic equation $x^2-35 x+c=0$ are in the ratio $2: 3$ and $c=6 \mathrm{~K}$, then…

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