If the roots of the equation $x^3+3 p x^2+3 q x-8=0$ are in a geometric progression, then $\frac{q^3}{p^3}=$

If the roots of the equation $x^3+3 p x^2+3 q x-8=0$ are in a geometric progression, then $\frac{q^3}{p^3}=$
  1. 1
  2. -2
  3. 4
  4. -8

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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