If the ratio of the concentration of electrons that of holes in a semiconductor is $\frac{7}{5}$ and the ratio of currents is $\frac{7}{4}$, then what is the ratio of their drift velocities?

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Aicharya · Accepted Answer

$\frac{\mathrm{n}_{\mathrm{e}}}{\mathrm{n}_{\mathrm{n}}}=\frac{7}{5} \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}}=\frac{7}{4}$ $\frac{\left(\mathrm{V}_{\mathrm{d}}ight)_{\mathrm{e}}}{\left(\mathrm{V}_{\mathrm{d}}ight)_{\mathrm{n}}} \Rightarrow \frac{\mathrm{l}_{\mathrm{e}}}{\mathrm{l}_{\mathrm{n}}} 	imes \frac{\mathrm{n}_{\mathrm{n}}}{\mathrm{n}_{\mathrm{e}}}=\frac{5}{4}$

If the ratio of the concentration of electrons that of holes in a semiconductor is $\frac{7}{5}$ and the…

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