If the ratio of the absolute temperature of the sink and source of a Carnot engine is changed from $2: 3$ to $3: 4$, the efficiency of the engine changes by

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Aicharya · Accepted Answer

For carnot engine, $\begin{aligned} & \eta_1=1-\frac{T_2}{T_1}=1-\frac{2}{3}=\frac{1}{3} \ & \eta_2=1-\frac{T_2^{\prime}}{T_1^{\prime}}=1-\frac{3}{4}=\frac{1}{4} \ & \% 	ext { change in } \eta=\frac{\eta_1-\eta_2}{\eta_1} 	imes 100 \ & =\frac{\frac{1}{3}-\frac{1}{4}}{\frac{1}{3}} 	imes 100=25 \% \end{aligned}$

If the ratio of the absolute temperature of the sink and source of a Carnot engine is changed from $2: 3$ to…

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