If the ratio of relative permeability and relative permittivity of a uniform medium is $1: 4$. The ratio of…

If the ratio of relative permeability and relative permittivity of a uniform medium is $1: 4$. The ratio of the magnitudes of electric field intensity $(E)$ to the magnetic field intensity $(H)$ of an EM wave propagating in that medium is (Given that $\sqrt{\frac{\mu_0}{\varepsilon_0}}=120 \pi$ )
  1. $30 \pi: 1$
  2. $1: 120 \pi$
  3. $60 \pi: 1$
  4. $120 \pi: 1$

Solution

$\frac{\mu_r}{E_r}=\frac{1}{4}$ $\frac{E}{H}=\frac{E \mu}{B}=v \mu$ $=\frac{1}{\sqrt{\mu \varepsilon}} \mu=\sqrt{\frac{\mu}{\varepsilon}}=\sqrt{\frac{\mu_0 \mu_r}{\varepsilon_0 \varepsilon_r}}$ $=\sqrt{\frac{\mu_0}{\varepsilon_0}} \sqrt{\frac{\mu_r}{\varepsilon_r}}$ $=120 \pi\left(\frac{1}{2}\right)$ $=\frac{60 \pi}{1}$ *

Asked in: NEET 2024 (Re-NEET)

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