If the radius of electron in the excited state of $\mathrm{He}^{+}$is $0.4232 \mathrm{~nm}$, the energy of…

If the radius of electron in the excited state of $\mathrm{He}^{+}$is $0.4232 \mathrm{~nm}$, the energy of electron in that excited state in $\mathrm{J}$ is : (The radius and energy of electron in the first orbit of hydrogen atom are $52.9 \mathrm{pm}$ and $-2.18 \times 10^{-18} \mathrm{~J}$ respectively)
  1. $-5.45 \times 10^{-17}$
  2. $-5.45 \times 10^{-19}$
  3. $5.45 \times 10^{18}$
  4. $5.45 \times 10^{-18}$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (26 Apr Shift 2)

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